Projectile Motion:- Horizontal and Vertical Components of Velocity

Q.1. Mike threw a ball upwards at an angle of 33 degrees to the horizontal at a speed of 36 m/s

(a) What was the horizontal component of the ball's velocity? (Nearest m/s)...............

(b) What was the vertical component of the ball's velocity? (Nearest m/s)...............

Q.2. Danielle entered the long jump and jumped upwards at an angle of 58 degrees to the horizontal with a takeoff speed of 63 m/s.

(a) What was the horizontal component of the Danielle's velocity? (Nearest m/s)...............

(b) What was the vertical component of the Danielle's velocity? (Nearest m/s)...............

Q.3. Sue fired a rifle upwards at an angle of 75 degrees to the horizontal. The bullet left the rifle with a speed of 20 m/s.

(a) What was the horizontal component of the bullet's velocity? (Nearest m/s)...............

(b) What was the vertical component of the bullet's velocity? (Nearest m/s)...............

Q.4. Nathan kicked a soccer ball upwards at an angle of 29 degrees to the horizontal at a speed of 45 m/s.

(a) What was the horizontal component of the ball's velocity? (Nearest m/s)...............

(b) What was the vertical component of the ball's velocity? (Nearest m/s)...............

Q.5. Sabrina threw a basketball upwards at an angle of 6 degrees to the horizontal at a speed of 45 m/s.

(a) What was the horizontal component of the basketball's velocity? (Nearest m/s)...............

(b) What was the vertical component of the basketball's velocity? (Nearest m/s)...............

Q.6. Dominic threw a stone upwards at an angle of " + 62 + " degrees to the horizontal at a speed of 27 m/s.

(a) What was the horizontal component of the stone's velocity? (Nearest m/s)...............

(b) What was the vertical component of the stone's velocity? (Nearest m/s)...............
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Answers:


For an object projected at an angle of θ to the horizontal the horizontal component of the velocity is v cos θ while the vertical component of the velocity is v sin θ.

Q.1. Mike threw a ball upwards at an angle of 33 degrees to the horizontal at a speed of 36 m/s
(a) What was the horizontal component of the ball's velocity? (Nearest m/s)...............

Horizontal component = v cosθ = 36 cos 33o = 30.192 = 30 ms-1 (nearest m/s)

(b) What was the vertical component of the ball's velocity? (Nearest m/s)...............

Vertical component = v sinθ = 36 sin 33o = 19.607 = 20 ms-1 (nearest m/s)

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Q.2. Danielle entered the long jump and jumped upwards at an angle of 58 degrees to the horizontal with a takeoff speed of 63 m/s.

(a) What was the horizontal component of the Danielle's velocity? (Nearest m/s)...............

Horizontal component = v cosθ = 63 cos 58o = 33.385 = 33 ms-1 (nearest m/s)

(b) What was the vertical component of the Danielle's velocity? (Nearest m/s)...............

Vertical component = v sinθ = 63 sin 58o = 53.427 = 53 ms-1 (nearest m/s)

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Q.3. Sue fired a rifle upwards at an angle of 75 degrees to the horizontal. The bullet left the rifle with a speed of 20 m/s.

(a) What was the horizontal component of the bullet's velocity? (Nearest m/s)...............

Horizontal component = v cosθ = 20 cos 75o = 5.176 = 5 ms-1 (nearest m/s)

(b) What was the vertical component of the bullet's velocity? (Nearest m/s)...............

Vertical component = v sinθ = 20 sin 75o = 19.319 = 19 ms-1 (nearest m/s)

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Q.4. Nathan kicked a soccer ball upwards at an angle of 29 degrees to the horizontal at a speed of 45 m/s.

(a) What was the horizontal component of the ball's velocity? (Nearest m/s)...............

Horizontal component = v cosθ = 45 cos 29o = 39.358 = 39 ms-1 (nearest m/s)

(b) What was the vertical component of the ball's velocity? (Nearest m/s)...............

Vertical component = v sinθ = 45 sin 29o = 21.816 = 22 ms-1 (nearest m/s)

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Q.5. Sabrina threw a basketball upwards at an angle of 6 degrees to the horizontal at a speed of 45 m/s.

(a) What was the horizontal component of the basketball's velocity? (Nearest m/s)...............

Horizontal component = v cosθ = 45 cos 6o = 44.753 = 45 ms-1 (nearest m/s)

(b) What was the vertical component of the basketball's velocity? (Nearest m/s)...............

Vertical component = v sinθ = 45 sin 6o = 4.704 = 5 ms-1 (nearest m/s)

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Q.6. Dominic threw a stone upwards at an angle of 62 degrees to the horizontal at a speed of 27 m/s.

(a) What was the horizontal component of the stone's velocity? (Nearest m/s)...............

Horizontal component = v cosθ = 27 cos 62o = 12.676 = 13 ms-1 (nearest m/s)

(b) What was the vertical component of the stone's velocity? (Nearest m/s)...............
Vertical component = v sinθ = 27 sin 62o = 23.840 = 24 ms-1 (nearest m/s)